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2x^2+11x+15=136^2
We move all terms to the left:
2x^2+11x+15-(136^2)=0
We add all the numbers together, and all the variables
2x^2+11x-18481=0
a = 2; b = 11; c = -18481;
Δ = b2-4ac
Δ = 112-4·2·(-18481)
Δ = 147969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{147969}=\sqrt{9*16441}=\sqrt{9}*\sqrt{16441}=3\sqrt{16441}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-3\sqrt{16441}}{2*2}=\frac{-11-3\sqrt{16441}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+3\sqrt{16441}}{2*2}=\frac{-11+3\sqrt{16441}}{4} $
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